Adafruit
USB to 2.1mm DC Booster Cable - 9V
This USB to DC booster cable has an integrated boost converter that steps up 5V USB power to 9V DC, output through a centre-positive 2.1 mm barrel jack. It's...
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This USB to DC booster cable has an integrated boost converter that steps up 5V USB power to 9V DC, output through a centre-positive 2.1 mm barrel jack. It's a convenient way to power 9V devices from any USB port — whether from a computer, USB wall charger, or battery pack.
Rated for 500 mA continuous output, the cable achieves up to 90% efficiency at low current draw. It's ideal for powering Arduino boards, effects pedals, routers, and other 9V devices without a dedicated power supply.
Key Features
- Integrated Boost Converter – Steps up 5V USB to 9V DC output
- 2.1 mm Centre-Positive Barrel Jack – Standard DC connector for 9V devices
- 500 mA Rated Output – Suitable for most 9V accessories
- Up to 90% Efficiency – Efficient power conversion at low to moderate loads
- 3 mA Quiescent Current – Low idle power consumption
Efficiency at Various Loads
- 50 mA – 9.0V output, ~90% efficiency
- 100 mA – 8.95V output, ~87% efficiency
- 200 mA – 8.9V output, ~86% efficiency
- 300 mA – 8.8V output, ~85% efficiency
- 500 mA – 8.8V output, ~83% efficiency
Ideal For
- Powering Arduino and other 9V dev boards from USB
- Guitar effects pedals and audio equipment
- Routers, modems, and small electronics
- Portable setups powered from USB battery packs
Package Contents
- 1× USB to 2.1 mm DC Booster Cable (9V)
Jargon buster
Plain-language definitions for the technical terms used above.
- boost converter
- A boost converter is a switching power circuit that raises a lower input voltage to a higher output voltage. It is used when a device needs more voltage than its power source provides, for example running a 5 V sensor from a 3.3 V supply.
- DC
- DC means direct current, where electricity flows in one constant direction, as supplied by batteries, USB ports and many plug-pack power supplies. When a product specifies DC, it runs from a DC supply rather than mains AC, so you need to provide the correct voltage and polarity.
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